Answer:
Coefficient of friction will be 0.587
Explanation:
We have given mass of the car m = 500 kg
Distance s = 18.25 m
Initial velocity of the car u = 14.5 m/sec
As the car finally stops so final velocity v = 0 m/sec
From second equation of motion
[tex]v^2=u^2+2as[/tex]
[tex]0^2=14.5^2+2\times a\times 18.25[/tex]
[tex]a=-5.76m/sec^2[/tex]
We know that acceleration is given by
[tex]a=\mu g[/tex]
[tex]5.76=\mu\times 9.81[/tex]
[tex]\mu =0.587[/tex]
So coefficient of friction will be 0.587