(a) D(c) = f + cx
(b) Delivery fee is $5.
(c) The cost per calendar is $19.
Step-by-step explanation:
Let,
Delivery fee = f
Cost of calendar = x
No. of calendars = c
Total cost with delivery fee = D
Therefore,
The cost of 2 calendars plus delivery fee is $43.
D(c)= f + cx
43 = f + 2x Eqn 1
The cost of 4 calendars plus delivery is $81.
D(c) = f + cx
81 = f +4x Eqn 2
(a)Write an equation that gives the total cost as a function of calendars bought.
D(c) = f + cx
(b)What is the delivery fee?
Multiplying Eqn 1 by 2;
[tex]2(43 = f + 2x)\\86=2f+4x\ \ \ Eqn\ 3[/tex]
Subtracting Eqn 2 from Eqn 3;
[tex](2f+4x)-(f+4x)=86-81\\2f+4x-f-4x=5\\f=5[/tex]
Delivery fee is $5.
(C)What is the cost per calendar?
Putting f=5 in Eqn 1;
[tex]43=5+2c\\43-5=2c\\2c=38\\[/tex]
Dividing both sides by 2
[tex]\frac{2c}{2}=\frac{38}{2}\\c=19[/tex]
The cost per calendar is $19.
Keywords: function, linear equation
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