Answer:
c. 75 joules
Explanation:
Work done(joules)=Force(newton)×Distance(meters)
Given: force=150-newton, Distance=0.5 meters
∴Work done=150×0.5=75 joules.
The amount of work done on the bucket will be 75 joules. Option C is correct.
Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Work may be zero, positive and negative.it depends on the direction of the body displaced. if the body is displaced in the same direction of the force it will be positive.
The given data in the problem is;
F is the force lift = 150-
d is the displacement = 0.5 meters
t is the time = 3 second
W is the amount of work done
The amount of work done on the bucket is found as;
[tex]\rm W = F \times d \\\\ W = 150 \times 0.5 \\\\ W=75 \ Joule[/tex]
Hence the amount of work done on the bucket will be 75 joules. Option C is correct.
To learn more about the work done refer to the link ;
https://brainly.com/question/3902440
