Question

Write the equations for the esterification process between ethanoic acid and 2-
propanol with sulphuric acid as catalyst.​

Answer 1

Answer: CH3COOH + CH3CHOHCH3 -> CH3COOCH(CH3)CH3 + H2O

Explanation: Estherification is the reaction between alkanoic acids and alkanols to porduce esters and what. ethanoic acid will react with 2-propanol to produce an ester and water.

Answer 2

Ethanoic acid reacts with 2-propanol to form an ester and water in the presence of sulfuric acid.



$\bold {CH_3COOH + CH_3CHOHCH_3 \rightarrow CH_3COOCH(CH_3)CH_3 + H_2O}$

What is Esterification?

• It is a type of reaction in which typically acid and alcohol react to form an ester product.

• The ester is derived from acid when the hydroxyl group is replaced by an alkyl group.

• Ethanoic acid reacts with 2-propanol to form an ester and water in the presence of sulfuric acid.

$\bold {CH_3COOH + CH_3CHOHCH_3 \rightarrow CH_3COOCH(CH_3)CH_3 + H_2O}$

Learn more about Esterification:

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