There are 55 quarters and 30 dimes in the machine.
Step-by-step explanation:
Total coins = 85
Total amount = $16.75 = 16.75*100 = 1675 cents
1 quarter = 25 cents
1 dime = 10 cents
According to given statement;
x+y=85 Eqn 1
25x+10y=1675 Eqn 2
Multiplying Eqn 1 by 10
[tex]10(x+y=85)\\10x+10y=850\ \ \ Eqn\ 3[/tex]
Subtracting Eqn 3 from Eqn 2
[tex](25x+10y)-(10x+10y)=1675-850\\25x+10y-10x-10y=825\\15x=825[/tex]
Dividing both sides by 15
[tex]\frac{15x}{15}=\frac{825}{15}\\x=55[/tex]
Putting in Eqn 1;
[tex]55+y=85\\y=85-55\\y=30[/tex]
There are 55 quarters and 30 dimes in the machine.
Keywords: linear equation, subtraction
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