Question

Length of rectangle is 5yd more than double the width,and the area of the rectangle is 42yd.find the dimension of the rectangle.

Answer 1

Answer:

width =6yd

length=17yd

Step-by-step explanation:

w=x

L=2x+5

area=L*w

42=x(2x+5)

$42=2x^{2} +5x$

$2x^{2} +5x-42=0$

$2x^{2}  -12x+7x-42=0$

2x(x-6)+7(x-6)=0

(x-6)(2x+7)=0

x-6=0

x=6

L=2x+5=2*6+5=12+5=17