Solution of system of linear equation y = 2x – 4 and 3x - 2y = 8 is x = 0 and y = -4
Need to determine solution of following system of linear equation
y = 2x – 4 ------(1)
3x - 2y = 8 ------(2)
If we observe the equation (1), we can say that we are having value of y in terms of x. so substitution method is the best approach to solve the above system of linear equation.
In substitution method, we will substitute value of y in equation (2) in terms of variable x from equation (1)
On substituting y = 2x – 4 in equation (2) , we get equation in one variable that is x which is as follows
3x – 2 (2x – 4 ) = 8
=> 3x – 4x + 8 = 8
=> -x = 8 – 8
=> x = 0
On substituting x = 0 in equation (1), we get
y = 2 x 0 – 4
=> y = -4
Hence solution of system of linear equation y = 2x – 4 and 3x - 2y = 8 is x = 0 and y = -4
