Answer:
1 mol of sucarose has 7.22 x10²⁴ atoms of C, 1.32 x10²⁵ atoms of H and 6.62 x10²⁴ atoms of O
Explanation:
C12H22O11 is the molecular formular for sucarose
So in 1 mol of sacarose, we have 12 mols of carbon, 22 moles of hydrogen, and 11 mols of oxygen.
As you know, 1 mol has 6.02x10²³ atoms so these are the rule of three to calculate the number of atoms of each type.
1 mol ______ 6.02x10²³
12 moles ______ 12 . 6.02x10²³ = 7.22 x10²⁴
22 moles ______ 22 . 6.02x10²³ = 1.32 x10²⁵
11 moles _______ 11 . 6.02x10²³ = 6.62 x10²⁴
