Find the x- and y intercepts for the linear equation

4. 3x + 2y = 6

5. 4x – 9y = 36

6. x + y = -3

8. Xx - 3y = 12

Respuesta :

4. 3x + 2y = 6

x-intercept = 2 ,  y - intercept = 3

5. 4x – 9y = 36

x-intercept = 9, y - intercept = -4

6. x + y = -3

x-intercept = -3, y - intercept = -3

8. x - 3y = 12

x-intercept = 12, y - intercept = -4

Step-by-step explanation:

To find the x-intercept we put y=0 in the equation and to find the y-intercept we put x = 0 in the equation

4. 3x + 2y = 6

Putting y = 0

[tex]3x + 2y = 6\\3x +2(0) = 6\\3x = 6\\\frac{3x}{3} = \frac{6}{3}\\x= 2[/tex]

Putting x=0

[tex]3x + 2y = 6\\3(0) + 2y = 6\\2y = 6\\\frac{2y}{2} = \frac{6}{2}\\y= 3[/tex]

5. 4x – 9y = 36

Putting y = 0

[tex]4x -9y = 36\\4x - 9(0) = 36\\4x = 36\\\frac{4x}{4} = \frac{36}{4}\\x = 9[/tex]

Putting x=0

[tex]4(0) -9y = 36\\-9y=36\\\frac{-9x}{-9} = \frac{36}{-9}\\x =-4[/tex]

6. x + y = -3

Putting y = 0

[tex]x+y=-3\\x+0 = -3\\x = -3[/tex]

Putting x=0

[tex]x + y = -3\\0+y=-3\\y=-3[/tex]

8. X - 3y = 12

Putting y=0

[tex]x - 3(0) = 12\\x -0 = 12\\x = 12[/tex]

Putting x = 0

[tex]0-3y = 12\\-3y = 12\\\frac{-3y}{-3} =\frac{12}{-3}\\y=-4[/tex]

Keywords: Linear equation

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