against the wind a small plane flew 245 miles in 1 hour and 10 minutes. The return trip took only 50 minutes. What was the speed of the wind? What was the speed of the plane in still air?​

Respuesta :

Answer:

speed of plane in still air  =  252 mph

speed of wind  = 42 mph.

Explanation:

Given:

Distance travelled by the small plane = 245  

Time taken to fly 245 miles =  1 hour and 10 minutes.

Time taken for return trip = 50 minutes.

To Find:

speed of the wind=?

The speed of the plane in still air=?​

Solution:

We Know that

[tex]speed = \frac{distance}{time}[/tex]  

=>[tex]\frac{245}{ \frac{70}{60}} hours[/tex]

=>[tex]\frac{245}{ \frac{7}{6}} hours[/tex]

=>[tex]245 \times { \frac{6}{7}[/tex]

=>210  mph against wind

on way back

=>[tex]\frac{245}{ \frac{50}{60}} hours[/tex]

=>[tex]\frac{245}{ \frac{5}{6}} hours[/tex]

=>[tex]245 \times { \frac{6}{5}[/tex]

=> 294

Now

294 = plane +wind------------------------(1)

210 =plane - wind-------------------------(2)

Solving (1) and (2)

2 plane = 504

plane = 252

plane = [tex]\frac{504}{2}[/tex]

So  substituting plane value in eq(2) we get,

210 =252 - wind

wind = 42 mph