Answer:
Step-by-step explanation:
[tex]\bold{METHOD\ 1:}\\\\\begin{array}{ccc}126\ mi&-&3h\\\\x\ mi&-&4h\end{array}\qquad\text{cross multiply}\\\\3x=(126)(4)\\3x=504\qquad\text{divide both sides by 3}\\x=168\ mi[/tex]
[tex]\bold{METHOD\ 2:}\\\\126\ mi\ \text{in}\ 3\ h,\ \text{then}\ \dfrac{126\ mi}{3}=42\ mi\ \text{in}\ 1\ h.\\\\\text{If}\ 42\ mi\ \text{in}\ 1\ h,\ \text{then}\ (42\ mi)(4)=168\ mi\ \text{in}\ 4h.[/tex]