Answer:
Step-by-step explanation:
[tex]-18x+2y\geq-13\qquad\text{add}\ 18x\ \text{to both sides}\\\\-18x+18x+2y\geq18x-13\\\\2y\geq18x-13\qquad\text{divide both sides by 2}\\\\\dfrac{2y}{2}\geq\dfrac{18x}{2}-\dfrac{13}{2}\\\\\boxed{y\geq9x-6.5}[/tex]