A weather balloon has a volume of 90.0 l when it is released from sea level. What
is the atmospheric pressure on the balloon when it has grown to a size of 175.0 1?

Respuesta :

The final atmospheric pressure is [tex]5.19\cdot 10^4 Pa[/tex]

Explanation:

Assuming that the temperature of the air does not change, we can use Boyle's law, which states that for a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume. In formula,

[tex]pV=const.[/tex]

where

p is the gas pressure

V is the volume

The equation can also be rewritten as

[tex]p_1 V_1 = p_2 V_2[/tex]

where in our problem we have:

[tex]p_1= 1.03\cdot 10^5 Pa[/tex] is the initial pressure (the atmospheric pressure at sea level)

[tex]V_1 = 90.0 L[/tex] is the initial volume

[tex]p_2[/tex] is the final pressure

[tex]V_2 = 175.0 L[/tex] is the final volume

Solving the equation for p2, we find the final pressure:

[tex]p_2 = \frac{p_1 V_1}{V_2}=\frac{(1.01\cdot 10^5)(90.0)}{175.0}=5.19\cdot 10^4 Pa[/tex]

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