The volume of the gas does not change
Explanation:
To solve this problem, we can apply the ideal gas equation, which states that:
[tex]\frac{pV}{T}=const.[/tex]
where
p is the pressure of the gas
V is its volume
T is its absolute temperature
The equation can also be written as
[tex]\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}[/tex]
where in this problem we have:
[tex]p_1[/tex] is the initial pressure of the gas
[tex]V_1[/tex] is the initial volume
[tex]T_1[/tex] is the initial temperature
[tex]p_2 = 2 p_1[/tex] is the final pressure (twice the initial pressure)
[tex]V_2[/tex] is the final volume
[tex]T_2 = 2T_1[/tex] is the final temperature (twice the initial temperature)
Solving for V2, we find what happens to the volume of the gas:
[tex]V_2 = \frac{p_1 V_1 T_2}{p_2 T_1}=\frac{p_1 V_1 (2T_1)}{(2p_1) T_1}=V_1[/tex]
Therefore, the volume of the gas does not change.
Learn more about ideal gases:
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