Question

Describe what would happen to the volume of a gas if
the pressure on it were decreased and then the gas's temperature
were increased.

Answer 1

The volume of the gas has increased

Explanation:

To solve this problem, we can use the ideal gas equation, which can be written as:

$\frac{pV}{T}=const.$

where:

p is the pressure of the gas

V is its volume

T is its absolute temperature

This equation can also be rewritten as follows:

$\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}$

where:

$p_1$ is the initial pressure of the gas

$V_1$ is the initial volume

$T_1$ is the initial temperature

$p_2$ is the final pressure

$V_2$ is the final volume

$T_2$ is the final temperature

In this problem:

- The pressure of the gas is decreased, so $p_2 < p_1$

- The temperature of the gas is increased, so $T_2 > T_1$

We can rewrite the equation making V2 the subject, to see what happens to the volume:

$V_2 = \frac{p_1 V_1 T_2}{p_2 T_1}=\frac{p_1}{p_2}\frac{T_2}{T_1} V_1$

Where we have:

$\frac{p_1}{p_2}>1$

$\frac{T_2}{T_1}>1$

Therefore, this implies that

$V_2 > V_1$

So the volume of the gas has increased.

Learn more about ideal gases:

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Answer 2

Answer:

Gases respond to changes in pressure, temperature, and volume in predictable ways, and according to Boyle's law, when the volume of gas decreases, the pressure increases. Therefore, when the pressure is decreased and temperature increased, the volume would also increase.