Answer:
The graph that passes through (-3,-3), (-3,0) and (-3,3) does not represents linear function
Step-by-step explanation:
Mariko says that the graph that passes through (-3,-3), (-3,0) and (-3,3)
Now, the line joining (-3,-3) and (-3,0) has slope = [tex]\frac{-3 - 0}{- 3 -(- 3)} =[/tex] = ∞
Again, the line joining (-3, 0) and (-3,3) has slope = [tex]\frac{0 - 3}{- 3 -(- 3)} =[/tex] = ∞
Therefore, both the lines are parallel to y-axis and has a common point (-3,0). {Since, tan Ф = ∞, ⇒ Ф = 90°}
So, the graph that passes through (-3,-3), (-3,0) and (-3,3) does not represents linear function as the graph represents a vertical line parallel to y-axis. (Answer)
