The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked [tex]1\frac{1}{5} \text{ or } \frac{6}{5}[/tex] miles.
Solution:
Given that,
To find total distance walked by Julian we have to add the above stated values. That is, [tex]\frac{6}{10} +\frac{35}{100} +\frac{1}{4}[/tex]
Factors of 10 = [tex]5\times2[/tex]
Factors of 100 = [tex]5\times2\times5\times2[/tex]
Factors of 4 = [tex]2\times2[/tex]
Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,
[tex]\frac{6\times10}{10\times10} +\frac{35\times1}{100\times1} +\frac{1\times25}{4\times1}\rightarrow\frac{60+35+25}{100}\rightarrow\frac{120}{100}[/tex]
[tex]\Rightarrow\frac{120}{100}\rightarrow\frac{6}{5}[/tex]
Which can also be written as [tex]1\frac{1}{5}[/tex].
So, from the above calculation it can be said that Julian walked [tex]1\frac{1}{5} \text{ miles }[/tex].