Question

Centrifuge is usually used to separate the various components in a whole blood. One intends to separate the red blood cells from the plasma in a sample of whole blood in a centrifuge of radius 0.350 m. If the mass of the red blood cell is 3.00 X 10-16 kg and the necessary force to separate the red blood cell from the plasma is 4.12 X 10-11 N, what is the angular speed the centrifuge should be operated?

Answer 1

Answer:

1084.94 rad/s

Explanation:

The force exerted in any circular motion is given by

$F = \frac{mv^2}{r}$

Where m is the mass of the mass of the body

v is the speed of the body and

r is the radius of the circular path

F is the centrifugal force

Substituting the given values in above equation, we get

$4.12 * 10^{-11} = \frac{3 * 10^{-16}^ v^2}{0.350}\\v = \sqrt{\frac{4.12 * 10^{-11} * 0.350}{3 * 10^{-16}} } \\v = 379.73$ m/s

For calculating angular velocity, "v" is to be divided by "r"

Angular velocity is equal to

$\frac{379.73}{0.35} \\1084.94$ rad/s