Respuesta :
Answer: 0.2
Step-by-step explanation:
We know that , the probability density function for uniform distribution is given buy :-
[tex]f(x)=\dfrac{1}{b-a}[/tex], where x is uniformly distributed in interval [a,b].
Given : The time to process a loan application follows a uniform distribution over the range of 8 to 13 days.
Let x denotes the time to process a loan application.
So the probability distribution function of x for interval[8,13] will be :-
[tex]f(x)=\dfrac{1}{13-8}=\dfrac{1}{5}[/tex]
Now , the probability that a randomly selected loan application takes longer than 12 days to process will be :-
[tex]\int^{13}_{12}\ f(x)\ dx\\\\=\int^{13}_{12}\dfrac{1}{5}\ dx\\\\=\dfrac{1}{5}[x]^{13}_{12}\\\\=\dfrac{1}{5}(13-12)=\dfrac{1}{5}=0.2[/tex]
Hence, the probability that a randomly selected loan application takes longer than 12 days to process = 0.2
The probability a loan application takes no longer than 12 days is 0.1666
- Range = 8 to 13 days
- Maximum number of days = 12
The probability a loan takes no longer than 12 days
Let x = time to process a loan application
for a uniform distribution (8, 13)
[tex]f(x) = \frac{1}{6} ; 8 < x < 13[/tex]
The probability is
[tex]Pr[x > 12] = \int\limits^1^3_1_2 {f(x)} \, dx = 1/6\int_1_2^1^3 dx = \frac{13-12}{6} = 1/6[/tex]
The probability a loan application takes no longer than 12 days is 0.1666
Learn more on uniform distribution here;
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