Answer: Minimum global acc when you substitute t = 0 in equation 2
Acc = 23.52m/s^2.
Global max acc = 35.595684524m/s^2
Explanation:
(t)= 0.001490833t^3-.08389t^2+23.52t+7.3(in feet per second). ...equation 1.
Equation 1 is the model showing the velocity pathway..
To derive the equation of acceleration.
We differentiate equation 1
DV(t)/Dt = acc. = .004472499t^2 - 0.16778t + 23.52...equ 2
Minimum global acc when you substitute t = 0 in equation 2
Acc = 23.52m/s^2.
Maximum global acc when you substitute the = 74s
Acc = 24.491404524 -12.41572 +23.52
Global max acc = 35.595684524m/s^2