Calculate to three significant digits the density of sulfur hexafluoride gas at exactly 15°C and exactly 1atm . You can assume sulfur hexafluoride gas behaves as an ideal gas under these conditions.

Respuesta :

Answer: 6.18 g/L

Explanation:

To calculate the density of gas, we use the equation given by ideal gas equation:

[tex]PV=nRT[/tex]

Number of moles (n) can be written as: [tex]n=\frac{m}{M}[/tex]

where, m = given mass

M = molar mass

[tex]PV=\frac{m}{M}RT\\\\PM=\frac{m}{V}RT[/tex]

where,

[tex]\frac{m}{V}=d[/tex] which is known as density of the gas

The relation becomes:

[tex]PM=dRT[/tex]    .....(1)

We are given:

M = molar mass of [tex]SF_6[/tex] =  146.06 g/mol

R = Gas constant = [tex]0.0821\text{ L atm }mol^{-1}K^{-1}[/tex]

T = temperature of the gas = [tex]15^oC=[15+273]K=288K[/tex]

P = pressure of the gas = 1 atm

Putting values in equation 1, we get:

[tex]1atm\times 146.06g/mol=d\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 288K\\\\d=6.18g/L[/tex]

Thus density of sulfur hexafluoride gas at exactly 15°C and exactly 1atm is 6.18g/L

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