Answer:
Step-by-step explanation:
Given
no of houses that can be served by water is directly Proportional to the square of diameter
[tex]N\propto d^2[/tex]
[tex]N=kd^2[/tex]
where k =constant
10 cm diameter can supply 40 houses
[tex]40=k(10)^2[/tex]-----------1
For d=30 cm Pipe
[tex]N_1=k(30)^2[/tex]-------------2
divide 1 & 2
[tex]\frac{N_1}{40}=(\frac{30}{10})^2[/tex]
[tex]N_1=40\times 9=360 [/tex]
(b)for N=1440 houses
[tex]1440=k(d_2)^2[/tex] ----------------3
[tex]\frac{1440}{40}=(\frac{d_2}{10})^2[/tex]
[tex]d_2=6\times 10[/tex]
[tex]d_2=60 cm[/tex]