Answer:
The wavelength of the station’s signal is 2.9 meters
The energy of a photon of the station’s electromagnetic signal is [tex]6.9\times10^{-26}J [/tex]
Explanation:
Wavelength [tex] \lambda [/tex] is inversely proprtional to frequency (f) and directly proportional to velocity of the wave (v).
[tex]\lambda=\frac{v}{f} [/tex] (1)
But electromagnetic waves as radio signals travel at speed of light so using this on (1):
[tex]\lambda=\frac{c}{f}=\frac{3.0\times10^{8}}{104.5\times10^{6}}\approx2.9\,m [/tex]
Albert Einstein discovered that energy of electromagnetic waves was quantized in small discrete packages of energy called photons with energy:
[tex] E=hf=(6.6\times10^{-34})(104.5\times10^{6})\approx6.9\times10^{-26}J[/tex]
with h the Planck's constant.