Answer:
0.28198 m/s²
0.02874
Explanation:
A = Amplitude = 1.4 m
T = Time period = 14 s
g = Acceleration due to gravity = 9.81 m/s²
Acceleration is given by
[tex]a=\omega^2A\\\Rightarrow a=\left(\frac{2\pi}{T}\right)^2A\\\Rightarrow a=\left(\frac{2\pi}{14}\right)^2\times 1.4\\\Rightarrow a=0.28198\ m/s^2[/tex]
The maximum acceleration of the passengers during this motion is 0.28198 m/s²
Dividing this value by g
[tex]\frac{a}{g}=\frac{0.28198}{9.81}\\\Rightarrow a=0.02874g[/tex]
The fraction of g is 0.02874