Answer:
[tex](64-16\pi) in.[/tex]
Step-by-step explanation:
Given:
radius = 2 in.
Since 4 circles are circumscribed by a square, then the side length of the square is 8
Area of Square = [tex]side^2=8^2=64in^2[/tex]
Area of 1 circle = [tex]2\times \pi \times r = 2\pi2=4\pi[/tex]
Area of 4 circles = 4 × Area of 1 Circle = [tex]4 \times 4\pi=16\pi[/tex]
According to the question, these four circle are removed by the above square.
Therefore, Remaining Area of the square after removing these four circle= Area of the square- area of 4 circles = [tex]64-16\pi \ in^2[/tex]
Hence Area of remaining square is [tex]64-16\pi \ in^2[/tex]
Answer:
C. on Edge
Step-by-step explanation:
I just took the test
