Answer:
9/32
Step-by-step explanation:
given that an ant is moving on a numbered, horizontal line every second
Probability for moving left = 1/4
and prob for moving right =3/4
As this totals 1, there is no chance that ant will remain in the same posiiton after 1 second.
Either it has to move left or right.
Initial position is 0.
After 3 seconds it is in position 1.
The chances are I second move left, next second, move right and come to 0 and third second move to 1.
Or
I second move right, then left to 0, and third again to right to 1.
There are no other alternatives
Probability for this = [tex]\frac{1}{4} \frac{3}{4} \frac{3}{4} +\frac{3}{4} \frac{1}{4} \frac{3}{4} \\=\frac{9}{32}[/tex]