Answer:
No. we cannot believe it as per hypothesis test done.
Step-by-step explanation:
Given that five hundred draws are made at random with replacement from a box of numbered tickets; 276 are positive.
To test the claim whether the proportion for positive numbers is 50% let us conduct a hypothesis test for proportions.
[tex]H_0: p =0.5\\H_a: p\neq 0.5[/tex]
(Two tailed test at 5% significance level)
Sample proportion p = [tex]\frac{276}{500} =0.552[/tex]
Std error of p = [tex]\sqrt{\frac{P(1-P)}{500} } \\=0.02236[/tex]
(assuming null hypothesis to be true)
Here P = 0.50
Test statistic = p difference/std error = [tex]\frac{0.052}{0.02236} \\=2.33[/tex]
Z test is used for this proportion.
p value = 0.0198
Since p value <0.05 we reject null hypothesis
At 95% confidence level, there is statistical evidence to show that sample mean is not 50%