The weights of the fish in a certain lake are normally distributed with a mean of 18 lb and a standard deviation of 18 . If 15 fish are randomly selected, what is the probability that the mean weight will be between 16.6 and 21.6 lb?

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Answer:

0.3991

Step-by-step explanation:

Given that the weights of the fish in a certain lake are normally distributed with a mean of 18 lb and a standard deviation of 18 .

we know that when a sample is taken mean would be the same but std error would vary

when a sample of size 15 is taken we have

[tex]n=15[/tex]

Standard error of sample = [tex]\frac{\sigma}{\sqrt{n} } \\=2.065[/tex]

the probability that the mean weight will be between 16.6 and 21.6 lb

[tex]=P(16.6<x<21.6)\\=P(-0.30<z<0.77)\\=0.3991[/tex]

So we get the required probability as

0.3991

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