Question

A crate with a mass of 186 kg sits flat on a horizontal surface. If the person slides the crate with constant velocity across the floor with a force of 273 N, what is the coefficient of kinetic friction between the crate and the floor?

Answer 1

Answer:

0.15

Explanation:

mass, m = 186 kg

Force, F = 273 N

Let μ be the coefficient of friction

As the block is moving with constant velocity so acceleration is zero.

Let f be the friction force.

F - f = ma

273 - f = 0

f = 273

μ mg = 273

μ x 186 x 9.8 = 273

μ = 0.15

Thus, the coefficient of friction is 0.15.