Answer: 90% confidence interval would be (66.92,69.08).
Step-by-step explanation:
Since we have given that
Number of kittens = n = 35
Mean = 68 days
Standard deviation = 3.9 days
We need to find the 90% confidence interval.
So, z= 1.645
So, intervals would be
[tex]\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=68\pm 1.645\times \dfrac{3.9}{\sqrt{35}}\\\\=68\pm 1.08\\\\=(68-1.08,68+1.08)\\\\=(66.92,69.08)[/tex]
Hence, 90% confidence interval would be (66.92,69.08).