Question

The magnetic flux through a coil of wire changes from 20 T·m2 to zero in a time of 0.50 s. What is the magnitude of the average voltage induced in the coil during this change? The magnitude of the average voltage induced in the coil is V.

Answer 1

To develop this problem, it is necessary to apply the concepts related to energy based on the Magnetic Flow of these systems.

The definition covered by this concept is

$E = \frac{\Delta \phi}{t}$

Where,

$\Delta \phi =$ the change in flux

t = time

Our values are given as,

$\phi_2 = 20Tm^2$

$\phi_1 = 0$

Expressed in terms of total change would be

$\Delta \phi = \phi_2-\phi_1$

$\Delta \phi = 20-0$

$\Delta \phi = 20Tm^2$

Replacing in our equation we have,

$E = \frac{\Delta \phi}{t}$

$E = \frac{20}{0.50}$

$E = 40V$

Therefore the  magnitude of the average voltage induced in the coil is 40V.