The given statement"If the pressure of a gas sample is quadrupled and the absolute temperature is doubled" is false.
Answer: Option B
Explanation:
As we know the direct relationship between Pressure and Temperature by the Gay-Lussac’s Law,
[tex]P_{1} T_{1}=P_{2} T_{2}[/tex]
From this, we get,
[tex]\frac{P_{1}}{T_{2}}=\frac{P_{2}}{T_{1}}[/tex]
[tex]T_{2}=\frac{P_{1} T_{1}}{P_{2}}[/tex]
So, according to given statement, we have [tex]P_{2} = 4 P_{1}[/tex]
Then from the above expression, we can find out the value of [tex]T_{2}[/tex] when pressure increased by 4 times of initial pressure as,
[tex]T_{2}=\frac{P_{1} T_{1}}{4 P_{1}}[/tex]
Hence, we get,
[tex]T_{1}=4 T_{2}[/tex]
Hence, from the above expression we can say that as we increase the pressure four times, the temperature does not get doubled. So, the given statement in the question is false.