Suppose you cross a pea plant with yellow, smooth seeds with one that has wrinkled, green seeds. You examine the seeds of 967 offspring and find that some have yellow, smooth seeds and some have yellow, wrinkled seeds, but no green seeds of either type show up. What is the genotype of the yellow-seeded parent? (Y = yellow, y = green; S = smooth, s = wrinkled)

Respuesta :

Answer:

The genotype of the yellow- seeeded plant will be YYSs.

Explanation:

A dominant trait can be described as a trait which has alleles to suppress the recessive allele. A recessive allele is the one which gets masked by the dominant allele and hence, its effect is not shown in the phenotype.

If the alleles for a trait are homozygous dominant in a parent, then none of the offsprings will carry the recessive trait. Hence, as we can see that none of the 967 offsprings has green colour that means the alleles for this trait were homozygous in one of the yellow- seeded parent (YY).

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