Question

A roller coaster speeds up with constant acceleration for 2.3 s until it reaches a velocity of 35 m/s. During this time, the roller coaster travels 41m. What is the initial velocity of the roller coaster before it begins to accelerate?

Answer 1

Answer:

0.65 m/s

Explanation:

Applying the equation,

v = u + at

35 = u + a×2.3    -(1)

Again, applying the equation,

s = ut + $\frac{1}{2}$a$t^{2}$

41 = u×2.3 +  $\frac{1}{2}$ × $(2.3)^{2}$

35.65 = 2u + 2.3a -(2)

comparing first and second we get u= 0.65 m/s

Answer 2

Answer:

x=(v+v0)/2 t

Explanation: