The average rate of change of f on the interval 0 ≤ x ≤ 2 equals 4
You haven't provided any function, so I can't help you in an exact way. However, I'll help you choosing a quadratic function. This type of functions are given by the form:
[tex]f(x)=ax^2+bx+c \\ \\ a,b,c \ real \ constants[/tex]
On the other hand, the average rate of change is defined as:
[tex]ARC=\frac{Change \ in y}{Change \ in \ x} \\ \\ ARC=\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}[/tex]
So, let's choose:
[tex]f(x)=x^2+2x+4[/tex]
We have the interval:
[tex]0\leq x\leq 2[/tex]
So:
[tex]x_{1}=0 \\ \\ x_{2}=2 \\ \\ f(x_{1})=0^2+2(0)+4=4 \\ \\ f(x_{2})=2^2+2(2)+4=4+4+4=12[/tex]
[tex]ARC=\frac{12-4}{2-0} \\ \\ ARC=\frac{8}{2} \\ \\ \boxed{ARC=4}[/tex]
Average Rate of Change: https://brainly.com/question/7666020
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