Question

An object has 60 J of potential energy and 40 J of kinetic energy. Then 10 J of the potential energy is converted into kinetic energy. How much work was done on the object?

20 J

10 J

50 J

100 J

Answer 1

The work done on the object is 10 J

Explanation:

According to the work-energy theorem, the work done by a conservative force on an object is equal to the change in kinetic energy of the object. Mathematically:

$W=K_f - K_i$ (1)

where

W is the work done

$K_f$ is the final kinetic energy

$K_i$ is the initial kinetic energy

In this problem, the object has initially

$U_i = 60 J$ (initial potential energy)

$K_i = 40 J$ (initial kinetic energy)

Then, 10 J of potential energy are converted into kinetic energy, so the final potential and kinetic energy are:

$U_f = 60-10 = 50 J$

$K_f = 40+10 = 50 J$

And by applying (1), we find the work done:

$W=K_f - K_i = 50 - 40 = 10 J$

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