Question

After a 65 newton weight has fallen freely from rest a vertical distance of 5.3 meters, the kinetic energy of the weight is

Answer 1

Answer:

The kinetic energy of the weight is 344.5 J

Explanation:

Given that:

Force = F = 65 newton

distance = d = 5.3 meters

We have to find change in kinetic energy ΔK.E

Now we know that, initially kinetic energy was 0 So the formula we use will be:

Work done = Change in kinetic energy

Mathematically,

W =  ΔK.E

As we know W = F . d and  ΔK.E = K.E(final) - K.E(initial)

So by putting values:

F . d = K.E(final) - K.E(initial)

F . d = K.E(final)

As  K.E(initial) is 0 so by putting values of F and d

(65)* (5.3) =  K.E(final)

344.5 J =  K.E(final)

So the change in  K.E will also be 344.5 J

i hope it will help you!

Answer 2

Hence, the kinetic energy of the weight is 344.5 J

Kinetic energy is the energy possessed by a body as a result of its motion. The kinetic energy is given in Joules.

Given a body with a weight of 65N and vertical distance of 5.3 m, hence:

Change in Kinetic energy = weight * distance= 65N * 5.3 m = 344.5 J

Find out more at: https://brainly.com/question/17858145