Answer:
[tex]\csc (-x) = - \csc x = - ( - 5) = 5[/tex]
Period is 2π
Horizontal shift = 0
Step-by-step explanation:
We know that [tex]\sin (-x) = - \sin x[/tex] and as [tex]\csc x = \frac{1}{\sin x}[/tex], so, we can write [tex]\csc (-x) = - \csc x[/tex]
Therefore, the if [tex]\csc x = - 5[/tex] then [tex]\csc (-x) = - \csc x = - ( - 5) = 5[/tex] (Answer)
Now, the period of [tex]\csc x[/tex] is 2π, hence the period of [tex]\csc (- x)[/tex] is also 2π. (Answer)
Again. [tex]\csc ( - x) = \csc (-x + 0)[/tex], hence, the horizontal shift of [tex]\csc (- x)[/tex] is 0. (Answer)