Answer:
a) 2.1 × 10^-6 m b) 1.3 × 10^-4 m
Explanation:
The thermal expansion of super Invar 0.20 ×10^-6oC^-1 and the length of Super is 1.9 m
using the linear expansivity formula
ΔL = αLoΔt where ΔL is the change in length meters, α is the linear expansivity of Super Invar in oC^-1 and Δt is the change in temperature in oC. Substituting the value into the formula gives
ΔL = 0.2 × 10 ^-6 × 1.9 m ×5.5 = 2.1 × 10^-6 meters to two significant figure
b) the thermal expansion of steel is 1.3 × 10^-5 oC^-1 and the length of steel is 1.8 m
using the formula
ΔL of steel = 1.3 × 10^-5 × 1.8 × 5.5 = 1.3 × 10^-4 m to two significant figure.