Answer: 0.5
Step-by-step explanation:
For binary distribution with parameters p (probability of getting success in each trial) and n (Total trials) , we have
[tex]\sigma=\sqrt{np(1-p)}[/tex]
We are given that ,
Total batches of televisions : n=25
The probability of defects : p= 0.01
Here success is getting defective batch .
Then, the standard deviation for the number of defects per batch will be :-
[tex]\sigma=\sqrt{(25)(0.01)(1-0.01)}\\\\=\sqrt{(25)(0.01)(0.99)}\\\\=\sqrt{0.2475}\\\\=0.497493718553\approx0.5[/tex] [Rounedde to the nearest tenth.]
Therefore, the standard deviation for the number of defects per batch =0.5