Answer:
T = 94.59 degree C
Step-by-step explanation:
Given data:
P= 83.4 kPa
[tex]P= 83.4 \times 10^3 Pa \frac{1 bar}{10^5 Pa}[/tex]
P = 0.834 bar
for Saturated table
P = 0.8 bar T = 93.50 degree C
P = 0.9 bar T = 96.71 degree C
from interpolation method
[tex]\frac{0.834 - 0.8}{0.9 - 0.8} = \frac{z}{96.71 - 93.5}[/tex]
z = 1.0914
T = 93.5 + z = 94.59 degree C