Answer:
[tex]\delta=101.13 g/cm^3[/tex]
Explanation:
As can be seen in the Figure in a face-centered cubic unit cell you have:
In total:
[tex]n_{atom}=6*0.5+8*\frac{1}{8}=4 atoms[/tex]
Now, each side of the cell is 234 picometers (2.34e-8 cm) long
[tex]V_{cell}=L^3=(2.34e^{-8} cm)^3[/tex]
[tex]V_{cell}=1.28*10^{-23}cm^3[/tex]
Atoms per cm3:
[tex]n=\frac{4 atoms}{1.28*10^{-23}cm^3}[/tex]
[tex]n=3.12*10^{23} atoms/cm^3[/tex]
Expressing in mass:
[tex]\delta=3.12*10^{23} atoms/cm^3* \frac{1 mol}{6.022*10^{23}}*195.08 g/mol[/tex]
[tex]\delta=101.13 g/cm^3[/tex]