Respuesta :
Answer:
From three condition the it is proved that Δ ABC and Δ DEF are similar Triangles .
Step-by-step explanation:
Given as :
To Proof : Triangle Δ ABC and Triangle Δ DEF are similar
There are three methods for two Triangles to be similar
A ) SAS i.e side angle side
B ) AA i.e angle angle
C ) SSS i.e side side side
Now,
A) If two triangle have a pair of equal corresponding angles and sides are proportional then triangle are similar
So, If in Δ ABC and Δ DEF
∠ B = ∠ E
and , [tex]\dfrac{AB}{DE}[/tex] = [tex]\dfrac{BC}{EF}[/tex]
Then Δ ABC [tex]\sim[/tex] Δ DEF
I.e SAS similarity
B ) If two triangles have equal corresponding angles , then triangles are similar .
So, If in Δ ABC and Δ DEF
∠ B = ∠ E and ∠ A = ∠ D
Then Δ ABC [tex]\sim[/tex] Δ DEF
I.e AA similarity
C ) If two triangles have three pairs of corresponding sides proportional then triangles are similar .
So, If in Δ ABC and Δ DEF
[tex]\dfrac{AB}{DE}[/tex] = [tex]\dfrac{BC}{EF}[/tex] = [tex]\dfrac{AC}{DF}[/tex]
Then Δ ABC [tex]\sim[/tex] Δ DEF
I.e SSS similarity
Hence From three condition the it is proved that Δ ABC and Δ DEF are similar Triangles . answer
Answer: Neither
Step-by-step explanation:
Got it wrong bc of the person it top of me but yea