Partamos definiendo la expresión del perÃodo, el cual esta dada por
[tex]T = 2 \pi \sqrt {\frac {l} {g}}[/tex]
Where,
l = length
g = Gravity
Of these options gravity on earth remains constant, so the only variable to move is length.
The length is directly proportional to the period, the longer it is, the higher the value of the period of the object will be. If the object goes too fast, it is necessary to increase the length.
From the options given above when adding length it is also inferred that weight is added, so the correct option would be Raise the Weight