Answer: [tex]\mu_x=18\text{ hours}[/tex]
[tex]\sigma_x=4\text{ hours}[/tex]
Step-by-step explanation:
We know that mean and standard deviation of sampling distribution is given by :-
[tex]\mu_x=\mu[/tex]
[tex]\sigma_x=\dfrac{\sigma}{\sqrt{n}}[/tex]
, where [tex]\mu[/tex] = population mean
[tex]\sigma[/tex] =Population standard deviation.
n= sample size .
In the given situation, we have
[tex]\mu=18\text{ hours}[/tex]
[tex]\sigma=6\text{ hours}[/tex]
n= 2
Then, the expected mean and the standard deviation of the sampling distribution will be :_
[tex]\mu_x=\mu=18\text{ hours}[/tex]
[tex]\sigma_x=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{2}}=4.24264068712\approx4[/tex] [Rounded to the nearest whole number]
Hence, the the expected mean and the standard deviation of the sampling distribution :
[tex]\mu_x=18\text{ hours}[/tex]
[tex]\sigma_x=4\text{ hours}[/tex]