Adam burnt 631.6 calories approximately
Given that, Adam swam 1500m in 19 minutes.
If swimming at a rate of 4.5km/h burns 600 calories,
we have to find how many calories did adam burn?
Now, let us find his rate of swimming
Distance travelled = speed rate x time taken
[tex]\begin{array}{l}{1500 \mathrm{m}=\text { rate } \times 19 \text { minutes }} \\\\ {1500 \times 1 \mathrm{m}=\text { rate } \times 19 \times 1 \text { minute }}\end{array}[/tex]
We know that 1 hour = 60 minutes and also 1 kilometer = 1000 meter
[tex]\begin{array}{l}{1500 \times \frac{1}{1000} \mathrm{km}=\text { rate } \times 19 \times \frac{1}{60} \text { hour }} \\\\ {\frac{1500}{1000}=r a t e \times \frac{19}{60}} \\\\ {\text { Rate }=\frac{60}{19} \times \frac{3}{2}} \\\\ {\text { Rate }=\frac{30}{19} \times 3} \\\\ {\text { Rate }=\frac{90}{19}=4.736 \mathrm{km} / \mathrm{h}}\end{array}[/tex]
Now, we know that, swimming at a rate of 4.5km/h burns 600 calories,
Let "n" be the calories burnt when adam swam 1500 meter in 19 minutes
[tex]\begin{array}{l}{4.5 \mathrm{km} / \mathrm{h} \rightarrow 600 \text { calories }} \\\\ {\text {Then, } 4.736 \mathrm{km} / \mathrm{h} \rightarrow \text { n calories. }}\end{array}[/tex]
Now, by criss cross multiplication method,
[tex]\begin{array}{l}{4.5 \times n=4.736 \times 600} \\\\ {\rightarrow 4.5 n=2842.1052} \\\\ {\rightarrow n=631.578}\end{array}[/tex]
Hence, adam burnt 631.6 calories approximately.