Question

3-) A farm truck moves due east with a constant velocity of 9.50 m/s on a limitless, horizontal stretch of
road. A boy riding on the back of the truck throws a can of soda upward (Fig. P4.54) and catches the
projectile at the same location on the truck bed, but 16.0 m farther down the road.

(a) in the frame of reference of the truck, at what angle does the boy throw the can? .
(b) What is the initial speed of the can relative to the truck?

Answer 1

given,

constant velocity = 9.50 m/s

acceleration = 0

distance = 16 m

the time of flight

 s = so + ut + 1/2at²

16 = 9.50 × t

t = 1.68 s

a) to catch the can the truck he must throw it  straight up, at 0° to the vertical.

b) now,

yf = Yi + UyT + 1/2at²

0 = 0 + Uy * 1.68 - 1/2 * 9.8 * 1.68²

Uy = 8.23 m/s