Question

A copper-constantan thermocouple generates a voltage of 4.75 x 10-3 volts when the temperature of the hot junction is 110 °C and the reference junction is kept at 0 °C. If the voltage is proportional to the difference in temperature between the junctions, what is the temperature in degrees Celsius of the hot junction when the voltage is 1.76 x 10-3 volts?

Answer 1

Answer:

The temperature of the hot junction is 40.7°C.

Explanation:

Given that,

Voltage $V=4.75\times10^{-3}\ volts$

Voltage $V'=1.76\times10^{-3}\ volt$

Temperature of hot junction = 110°C

If the voltage is proportional to the difference in temperature between the junctions,

We need to calculate the temperature of the hot junction

Using formula of temperature

$\dfrac{V}{V'}=\dfrac{\Delta T}{\Delta T}$

$\dfrac{V}{V'}=\dfrac{T_{2}-T_{1}}{T_{2}-T_{1}}$

Here,T₁=0°C

$\dfrac{V}{V'}=\dfrac{110}{T_{2}}$

Put the value into the formula

$\dfrac{4.75\times10^{-3}}{1.76\times10^{-3}}=\dfrac{110}{T_{2}}$

$T_{2}=\dfrac{110\times1.76\times10^{-3}}{4.75\times10^{-3}}$

$T_{2}=40.7^{\circ}C$

Hence, The temperature of the hot junction is 40.7°C.