Answer: a) 0.68, 0.1043, b) 0.68, 0.066
Step-by-step explanation:
Since we have given that
p = 0.68
n= 20
Expected value = 0.68
So, Standard error would be
[tex]\sqrt{\dfrac{p(1-p)}{n}}\\\\=\sqrt{\dfrac{0.68\times 0.32}{20}}\\\\=0.1043[/tex]
if n = 50
Expected value = 0.68
So, Standard error would be
[tex]\sqrt{\dfrac{p(1-p)}{n}}\\\\=\sqrt{\dfrac{0.68\times 0.32}{50}}\\\\=0.0659\approx 0.066[/tex]
In both the cases,
Yes it is appropriate to use the normal distribution for expected value and standard error.