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A boat on a river travels downstream between 2 points 20 miles apart in 1 hour. It makes its return trip against the current and it takes 2 ½ hours. What are the speed of the boat and the speed of the current?

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AL2006

There are two unknown quantities that we have to find.  In order to work with them, we have to give them temporary names.  Lets call the speed of the boat ' B ', and lets call the speed of the current ' C ' .

-- "Downstream", the current is helping the boat.  The boat sails past the trees at a speed of (B + C).

(Distance) / (Speed) = Time

(20 miles) / (B + C) = 1 hour

Multiply each side by (B+C), then divide by 1 hr:  20 mi/1 hr = B + C

-- "Upstream" the boat is going against the current. It sails past the trees at a speed of (B - C).

(Distance) / (Speed) = Time

(20 miles) / (B - C) = 2.5 hours

Multiply each side by (B-C), then divide by 2.5 hr: 20 mi/2.5 hr = B - C

We're in good shape now. We have 2 equations in 2 unknowns:

B + C = 20

B - C =  8

Add the two equations, and you get 2B = 28. So B = 14 mph

Subtract the two equations and you get 2C = 12. So C = 6 mph

The speed of the boat is 14 mph .

The speed of the current is 6 mph .

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